Tyler (Jones Beach)@fromscratchcode.comWow, I'd never actually thought about how this impacts the AST. a == b == c is actually evaluated as (a == b) and (b == c) which is different than something like 1 + 2 + 3 which gets evaluated as (1 + 2) + 32/10/25, 10:13 pm·0 reposts·0 likes